Question
If $A=\left[\begin{array}{cc}2 & 0 \\ -3 & 1\end{array}\right]$ and $B=\left[\begin{array}{cc}0 & 1 \\ -2 & 3\end{array}\right]$ find $2 A-3 B$

Answer

$\begin{aligned} & A=\left[\begin{array}{cc}2 & 0 \\ -3 & 1\end{array}\right] \\ & B=\left[\begin{array}{cc}0 & 1 \\ -2 & 3\end{array}\right] \\ & \therefore 2 A-3 B=2\left[\begin{array}{cc}2 & 0 \\ -3 & 1\end{array}\right]-3\left[\begin{array}{cc}0 & 1 \\ -2 & 3\end{array}\right] \\ & =\left[\begin{array}{cc}4 & 0 \\ -6 & 2\end{array}\right]-\left[\begin{array}{cc}0 & 3 \\ -6 & 9\end{array}\right] \\ & =\left[\begin{array}{cc}4-0 & 0-3 \\ -6+6 & 2-9\end{array}\right] \\ & =\left[\begin{array}{cc}4 & -3 \\ 0 & -7\end{array}\right] .\end{aligned}$

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