Question
If $A=\left[\begin{array}{cc}2 & 1 \\ 0 & -2\end{array}\right]$ and $B=\left[\begin{array}{cc}4 & 1 \\ -3 & -2\end{array}\right], C=\left[\begin{array}{ll}-3 & 2 \\ -1 & 4\end{array}\right]$ Find $A^2+A C-5 B$

Answer

$
\begin{aligned}
& A=\left[\begin{array}{cc}
2 & 1 \\
0 & -2
\end{array}\right] \\
& B=\left[\begin{array}{cc}
4 & 1 \\
-3 & -2
\end{array}\right] \\
& C=\left[\begin{array}{ll}
-3 & 2 \\
-1 & 4
\end{array}\right] \\
& A^2+A C-5 B \\
& =\left[\begin{array}{cc}
2 & 1 \\
0 & -2
\end{array}\right]\left[\begin{array}{cc}
2 & 1 \\
0 & -2
\end{array}\right]+\left[\begin{array}{cc}
2 & 1 \\
0 & -2
\end{array}\right]\left[\begin{array}{ll}
-3 & 2 \\
-1 & 4
\end{array}\right]-5\left[\begin{array}{cc}
4 & 1 \\
-3 & -2
\end{array}\right]
\end{aligned}
$
(Substituting the values from questions)
$
\begin{aligned}
& =\left[\begin{array}{ll}
4+0 & 2-2 \\
0+0 & 0+4
\end{array}\right]+\left[\begin{array}{cc}
-6-1 & 0+4 \\
0+2 & -8
\end{array}\right]-5\left[\begin{array}{cc}
4 & 1 \\
-3 & -2
\end{array}\right] \\
& =\left[\begin{array}{ll}
4 & 0 \\
0 & 4
\end{array}\right]+\left[\begin{array}{cc}
-7 & 8 \\
2 & -8
\end{array}\right]-\left[\begin{array}{cc}
20 & 5 \\
-15 & -10
\end{array}\right] \\
& =\left[\begin{array}{cc}
4-7-20 & 0+8-5 \\
0+2+15 & 4-8+10
\end{array}\right] \\
& =\left[\begin{array}{cc}
-23 & 3 \\
17 & 6
\end{array}\right] .
\end{aligned}
$

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