Question
If $A=\left[\begin{array}{cc}2 & -2 \\ 4 & 3\end{array}\right]$ then find $A^{-1}$ by adjoint method.
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$\tan ^{-1}\left(\frac{2 x^{\frac{5}{2}}}{1-x^5}\right)$
$y = a +\frac{b}{x} ; x \frac{d^2 y}{d x^2}+2 \frac{d y}{d x}=0$