Question
If $A=\left[\begin{array}{cc}8 & 4 \\ 10 & 5\end{array}\right], B=\left[\begin{array}{cc}5 & -4 \\ 10 & -8\end{array}\right]$, show that $(A+B)^2=A^2+A B+B^2$.

Answer

We have to prove that $(A+B)^2=A^2+A B+B^2$

i.e, to prove $A^2+A B+B A+B^2=A^2+A B+B^2$,

i.e., to prove BA = 0.

$\begin{aligned} & B A=\left[\begin{array}{cc}5 & -4 \\ 10 & -8\end{array}\right]\left[\begin{array}{cc}8 & 4 \\ 10 & 5\end{array}\right] \\ & {\left[\begin{array}{ll}40-40 & 20-20 \\ 80-80 & 40-40\end{array}\right]=\left[\begin{array}{ll}0 & 0 \\ 0 & 0\end{array}\right]}\end{aligned}$

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