MCQ
If $A=\left[\begin{array}{ll}-1 & 5 \\ -3 & 2\end{array}\right]$, then adj $A=$
  • A
    $\left[\begin{array}{cc}2 & 3 \\ -5 & -1\end{array}\right]$
  • B
    $\left[\begin{array}{ll}1 & -5 \\ 3 & -2\end{array}\right]$
  • $\left[\begin{array}{ll}2 & -5 \\ 3 & -1\end{array}\right]$
  • D
    $\left[\begin{array}{ll}-2 & 5 \\ -3 & 1\end{array}\right]$

Answer

Correct option: C.
$\left[\begin{array}{ll}2 & -5 \\ 3 & -1\end{array}\right]$
(C) Matrix of co-factors $=\left[ A _{ ij }\right]_{2 \times 2}$
$=\left[\begin{array}{ll} A _{11} & A_{12} \\ A_{21} & A_{22}\end{array}\right]$
$=\left[\begin{array}{cc}2 & -(-3) \\ -5 & -1\end{array}\right]$
$=\left[\begin{array}{cc}2 & 3 \\ -5 & -1\end{array}\right]$
$\therefore \quad \operatorname{adj} A=\left[A_{i j}\right]_{2 \times 2}^T=\left[\begin{array}{cc}2 & 3 \\ -5 & -1\end{array}\right]^T=\left[\begin{array}{cc}2 & -5 \\ 3 & -1\end{array}\right]$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free