MCQ
If $A=\left[\begin{array}{ll}1 & 1 \\ 8 & 3\end{array}\right]$, then $A^2-4 A=$
- A$\left[\begin{array}{rr}-3 & -3 \\ 60 & 5\end{array}\right]$
- B$\left[\begin{array}{rr}-3 & -3 \\ 8 & 3\end{array}\right]$
- ✓$\left[\begin{array}{ll}5 & 0 \\ 0 & 5\end{array}\right]$
- D$\left[\begin{array}{cc}8 & 3 \\ 24 & 14\end{array}\right]$