Question
If $A=\left[\begin{array}{ll}1 & 2 \\ 3 & 4\end{array}\right]$ and $B=\left[\begin{array}{ll}2 & 1 \\ 4 & 2\end{array}\right], C=\left[\begin{array}{ll}5 & 1 \\ 7 & 4\end{array}\right]$, compute $(B+C) A$

Answer

$\begin{aligned} & (B+C) A \\ & A=\left[\begin{array}{ll}1 & 2 \\ 3 & 4\end{array}\right] \\ & B=\left[\begin{array}{ll}2 & 1 \\ 4 & 2\end{array}\right] \\ & C=\left[\begin{array}{ll}5 & 1 \\ 7 & 4\end{array}\right] \\ & (B+C) A=\left[\begin{array}{cc}7 & 2 \\ 11 & 6\end{array}\right] \times\left[\begin{array}{ll}1 & 2 \\ 3 & 4\end{array}\right] \\ & =\left[\begin{array}{cc}7+6 & 14+8 \\ 11+18 & 22+24\end{array}\right] \\ & =\left[\begin{array}{cc}13 & 22 \\ 29 & 46\end{array}\right] .\end{aligned}$

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