MCQ
If $A=\left[\begin{array}{rr}3 & 1 \\ -1 & 2\end{array}\right]$, then $A^2+5 A$ is:
  • A
    $\left[\begin{array}{ll}23 & 10 \\ 10 & 13\end{array}\right]$
  • B
    $\left[\begin{array}{ll}10 & 23 \\ 13 & 10\end{array}\right]$
  • C
    $\left[\begin{array}{ll}23 & 10 \\ 10 & 23\end{array}\right]$
  • $\left[\begin{array}{rr}23 & 10 \\ -10 & 13\end{array}\right]$

Answer

Correct option: D.
$\left[\begin{array}{rr}23 & 10 \\ -10 & 13\end{array}\right]$
(d) $\left[\begin{array}{rr}23 & 10 \\ -10 & 13\end{array}\right]$
Explanation:
$\begin{array}{l}A^2+5 A=A \cdot A+5 A \\ =\left[\begin{array}{rr}3 & 1 \\ -1 & 2\end{array}\right]\left[\begin{array}{rr}3 & 1 \\ -1 & 2\end{array}\right]+5\left[\begin{array}{rr}3 & 1 \\ -1 & 2\end{array}\right] \\ =\left[\begin{array}{rr}8 & 5 \\ -5 & 3\end{array}\right]+\left[\begin{array}{rr}15 & 5 \\ -5 & 10\end{array}\right] \\ =\left[\begin{array}{rr}23 & 10 \\ -10 & 13\end{array}\right]\end{array}$

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