MCQ
If $\alpha $ and $\beta $ are imaginary cube roots of unity, then ${\alpha ^4} + {\beta ^4}$ + $\frac{1}{{\alpha \beta }} = $
  • A
    $3$
  • $0$
  • C
    $1$
  • D
    $2$

Answer

Correct option: B.
$0$
b
(b) Complex cube root of unity are $1,\,\,\omega ,\,{\omega ^2}$
Let $\alpha = \omega ,\,\,\beta = {\omega ^2}$; Then ${\alpha ^4} + {\beta ^4} + {\alpha ^{ - 1}}{\beta ^{ - 1}}$
$ = {\omega ^4} + {({\omega ^2})^4} + ({\omega ^{ - 1}})\,\,{({\omega ^2})^{ - 1}} = \omega + {\omega ^2} + 1 = 0$.

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