MCQ
If $\alpha , \beta $ are two real numbers satisfying $\alpha^2 + \beta^2$ = $ 5$ and $3(\alpha^5 + \beta^5) = 11$$(\alpha^3 + \beta^3)$, then $\alpha \beta$ is
- ✓$2 $
- B$1$
- C$7$
- D$9$
$\frac{1}{\left(\alpha^{2}+\beta^{2}-\alpha \beta\right)}\left(\alpha^{4}+\beta^{4}-\alpha \beta\left(\alpha^{2}+\beta^{2}-\alpha \beta\right)\right)=\frac{11}{3}$
$\frac{\left(\alpha^{4}+\beta^{4}\right)}{\left(\alpha^{2}+\beta^{2}-\alpha \beta\right)}-\alpha \beta=\frac{11}{3}$
$\frac{25-2(\alpha \beta)^{2}}{5-\alpha \beta}-\alpha \beta=\frac{11}{3}$
Let $\alpha \beta=\mathrm{t} ;$ by cofficient $\alpha \beta=2$
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