If an electron revolves around a nucleus in a circular orbit of radius $R$ with frequency $n$, then the magnetic field produced at the centre of the nucleus will be
A$\frac{\mu_0 e n}{2 R}$
B$\frac{\mu_0 e n}{4 \pi R}$
C$\frac{4 \pi \mu_0 e n}{R}$
D$\frac{4 \pi \mu_0 e}{R n}$
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A$\frac{\mu_0 e n}{2 R}$
a (a)
Current $(i)=\frac{q}{T}=q\left(\frac{1}{T}\right)=q n$
So $\vec{B}=\frac{\mu_0 i}{2 R}=\frac{\mu_0(n e)}{2 R}$
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