MCQ
If an iron $(III)$ complex with the formula $\left[ \ce{Fe} \left( \ce{NH} _3\right)_{ x }( \ce{CN} )_{ y }\right]$, has no electron in its $e_g$ orbital, then the value of $x + y$ is
- A5
- B6
- C3
- D4
✓
Answer
Complex is $\left[ \ce{Fe} \left( \ce{NH} _3\right)_{ x }( \ce{CN} )_{ y }\right]^{\Theta}$
$ x=2$
$y=4$
so $ x+y=6 $
$ x=2$
$y=4$
so $ x+y=6 $
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