MCQ
If arithmetic mean of a distribution be $\bar{x},$ then its mean deviation is :
- A$\frac{\sum f_i\left(x_i-\bar{x}\right)}{ N }$
- B$\Sigma f_i\left|x_i-\bar{x}\right|$
- ✓$\frac{\Sigma f_i\left|\left(x_i-\bar{x}\right)\right|}{ N }$
- D$\frac{\sum f_i\left|x_i-\bar{x}\right|^2}{N}$