MCQ
If arithmetic mean of a distribution be $\bar{x},$ then its mean deviation is :
  • A
    $\frac{\sum f_i\left(x_i-\bar{x}\right)}{ N }$
  • B
    $\Sigma f_i\left|x_i-\bar{x}\right|$
  • $\frac{\Sigma f_i\left|\left(x_i-\bar{x}\right)\right|}{ N }$
  • D
    $\frac{\sum f_i\left|x_i-\bar{x}\right|^2}{N}$

Answer

Correct option: C.
$\frac{\Sigma f_i\left|\left(x_i-\bar{x}\right)\right|}{ N }$
C

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