Question
If $b^2=a c$. Prove that, $\log a+\log c=2 \log b$.
✓
Answer
$b^2=a c$
Taking log on both sides, we get
$\log b^2=\log a c$
$ \therefore 2 \log b=\log a+\log c$
$\therefore \log a+\log c=2 \log b$
Taking log on both sides, we get
$\log b^2=\log a c$
$ \therefore 2 \log b=\log a+\log c$
$\therefore \log a+\log c=2 \log b$
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