MCQ
If $\begin{vmatrix}2\text{x}&5\\8&\text{x}\end{vmatrix}=\begin{vmatrix}6&-2\\7&3\end{vmatrix},$ then x =
- A$3$
- B$\pm3$
- ✓$\pm6$
- D$6$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
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$\text{X}:$
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$1$
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$2$
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$3$
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$4$
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$\text{P}(\text{X}):$
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$\frac{1}{10}$
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$\frac{1}{5}$
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$\frac{3}{10}$
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$\frac{2}{5}$
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$f(x)=\left\{\begin{array}{rc}x^5+5 x^4+10 x^3+10 x^2+3 x+1, & x<0 \\ x^2-x+1, & 0 \leq x<1 \\ \frac{2}{3} x^3-4 x^2+7 x-\frac{8}{3}, & 1 \leq x<3 \\ (x-2) \log _e(x-2)-x+\frac{10}{3}, & x \geq 3\end{array}\right.$
Then which of the following options is/are correct?
$(1)$ $f^{\prime}$ has a local maximum at $x =1$ $(2)$ $f$ is onto
$(3)$ $f$ is increasing on $(-\infty, 0)$ $(4)$ $f^{\prime}$ is $NOT$ differentiable at $x =1$