Question
If $\Big(\text{x}+\frac{1}{\text{x}}\Big)=4$ Find the values of:
$\Big(\text{x}^2+\frac{1}{\text{x}^2}\Big)$

Answer

$\Big(\text{x}+\frac{1}{\text{x}}\Big)=4$
Squaring on both sides:
$\Big(\text{x}+\frac{1}{\text{x}}\Big)^2=(4)^2$
$\Rightarrow​​\text{x}^2+\frac{1}{\text{x}^2}+2\times\text{x}+\frac{1}{\text{x}}=16$
$\Rightarrow\text{x}^2+\frac{1}{\text{x}^2}+2=16$
$\Rightarrow\text{x}^2+\frac{1}{\text{x}^2}=16-2=14$
$\therefore\text{x}^2+\frac{1}{\text{x}^2}=14$

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