Question
If $Br^-$ configuration is $[Ar]\, 3d^{10}\,4s^2\,4p^6$ then $Br^{+2}$ configuration will be identical to which element ?
$Br ^{+2}$ is : $[ Ar ]\, 3 d ^{10} \,4 s ^2\, 4 p ^3$
The electronic configuration of $Br ^{+2}$ is hence identical with the element Arsenic.
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$(1)$ Oxidation of glucose with bromine water gives glutamic acid
$(2)$ The two six-membered cyclic hemiacetal forms of $D-(+)$-glucose ard called anomers
$(3)$ Hydrolysis of sucrose gives dextrorotatory glucose and laevorotatory fructose
$(4)$ Monosaccharides cannot be hydrolysed to give polyhydroxy aldehydes and ketones
$KMn{O_4} + {H_2}S{O_4} + {H_2}{O_4} \to {K_2}S{O_4} + MnS{O_4} + {O_2} + {H_2}O$
(Atomic masses of $\mathrm{Ag}$ and $\mathrm{Cl}$ are $107.87$ and $35.5$ respectively)
