MCQ
If $C = 2\cos \theta $, then the value of the determinant $\Delta = \left| {\,\begin{array}{*{20}{c}}C&1&0\\1&C&1\\6&1&C\end{array}\,} \right|$ is
  • A
    $\frac{{\sin 4\theta }}{{\sin \theta }}$
  • B
    $\frac{{2{{\sin }^2}2\theta }}{{\sin \theta }}$
  • C
    $4{\cos ^2}\theta \,(2\cos \theta - 1)$
  • None of these

Answer

Correct option: D.
None of these
d
(d) $\Delta = \left| {\,\begin{array}{*{20}{c}}C&1&0\\1&C&1\\6&1&C\end{array}\,} \right|\, = C[{C^2} - 1] - 1[C - 6]$

==> $\Delta = 2\cos \theta (4{\cos ^2}\theta - 1) - (2\cos \theta - 6)$
==> $\Delta = 8{\cos ^3}\theta - 4\cos \theta + 6$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If $-9 $ is a root of the equation $\left| {\,\begin{array}{*{20}{c}}x&3&7\\2&x&2\\7&6&x\end{array}\,} \right| = 0$ then the other two roots are
The sine and cosine curves intersects infinitely many times giving bounded regions of equal areas. The area of one of such region is
The tangent to the hyperbola $xy = c^2$  at the point $P$  intersects the $x-$ axis at $T$ and the $y-$ axis at $T'$. The normal to the hyperbola at $P$ intersects the $ x-$ axis at $N$  and the $y-$ axis at $N'$. The areas of the triangles $PNT$  and $PN'T' $ are $ \Delta$  and $ \Delta ' $ respectively, then $\frac{1}{\Delta }\,\, + \,\,\frac{1}{{\Delta '}}\,$ is
The integral $\int {\frac{{xdx}}{{2 - {x^2} + \sqrt {2 - {x^2}} }}} $ equals
The lowest integer which is greater than $\left(1+\frac{1}{10^{100}}\right)^{10^{100}}$ is $.....$
If  ${\mathop{\rm Im}\nolimits} \left( {\frac{{2z + 1}}{{iz + 1}}} \right) =  - 3,$ then locus of $z$ is :-
$\int \limits_{\pi / 6}^{\pi / 3} \tan ^{3} x \cdot \sin ^{2} 3 x\left(2 \sec ^{2} x \cdot \sin ^{2} 3 x+3 \tan x \cdot \sin 6 x\right) d x$ is equal to
If $x,y,z$  are in $A.P.$ and  ${\tan ^{ - 1}}x,{\tan ^{ - 1}}y$ and ${\tan ^{ - 1}}z$ are also in other $A.P.$ then  . . . 
Let $f(x) = [x]\sin \left( {\frac{\pi }{{[x + 1]}}} \right)$, where $[.]$ denotes the greatest integer function. The domain of $f$ is ….and the points of discontinuity of $f$ in the domain are
Let $A \equiv  (\lambda  + 2, 1 - 2\lambda , \lambda  + 2)$ and $B \equiv  (2k + 1, k, k +1)$ and $ \lambda , k  \in  R.$ Then minimum distance between $A$ and $B$ is -