Question
If $cos A = {3\over 4} , $ then $32\sin \left( {\frac{A}{2}} \right)\sin \left( {\frac{{5A}}{2}} \right) = $

Answer

c
(c) $32\sin \frac{A}{2}\sin \frac{{5A}}{2} = 16(\cos 2A - \cos 3A)$ 

$ = 16(2{\cos ^2}A - 1 - 4{\cos ^3}A + 3\cos A)$ 

$ = 16\left( {2 \times \frac{9}{{16}} - 1 - 4 \times \frac{{27}}{{64}} + 3 \times \frac{3}{4}} \right) = 11$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Let : $\overrightarrow{ a }=\hat{ i }+2 \hat{ j }+3 \hat{ k }, \overrightarrow{ b }=\hat{ i }-\hat{ j }+2 \hat{ k }$ and $\vec{c}=5 \hat{i}-3 \hat{j}+3 \hat{k}$ be there vectors. If $\vec{r}$ is a vector such that, $\overrightarrow{ r } \times \overrightarrow{ b }=\overrightarrow{ c } \times \overrightarrow{ b }$ and $\overrightarrow{ r } \cdot \overrightarrow{ a }=0$. Then $25|\overrightarrow{ r }|^2$ is equal to
If $S=\{z \in C:|z-i|=|z+i|=|z-1|\}$, then, $n(S)$ is:
The value of $\sum\limits_{r = 1}^{15} {{r^2}\,\left( {\frac{{^{15}{C_r}}}{{^{15}{C_{r - 1}}}}} \right)} $ is equal to
$\mathop {\lim }\limits_{n \to \infty } \frac{{n{{(2n + 1)}^2}}}{{(n + 2)({n^2} + 3n - 1)}} = $
Let $\mathrm{A}=\{\mathrm{z} \in \mathrm{C}:|\mathrm{z}-2-\mathrm{i}|=3\}$, $B=\{z \in C: \operatorname{Re}(z-i z)=2\}$ and $S=A \cap B$. Then $\sum_{z \in S}|z|^{2}$ is equal to _____________.
The number of rectangles that can be obtained by joining four of $12$ vertices of a $12$ - sided  regular polygon is:-
Let $\quad \overrightarrow{\mathrm{a}}=2 \hat{\mathrm{i}}+\alpha \hat{\mathrm{j}}+\hat{\mathrm{k}}, \quad \overrightarrow{\mathrm{b}}=-\hat{\mathrm{i}}+\hat{\mathrm{k}}, \quad \overrightarrow{\mathrm{c}}=\beta \hat{\mathrm{j}}-\hat{\mathrm{k}}$, where $\alpha$ and $\beta$ are integers and $\alpha \beta=-6$. Let the values of the ordered pair $(\alpha, \beta)$ for which the area of the parallelogram of diagonals $\vec{a}+\vec{b}$ and $\vec{b}+\vec{c}$ is $\frac{\sqrt{21}}{2}$, be $\left(\alpha_1, \beta_1\right)$ and $\left(\alpha_2, \beta_2\right)$. Then $\alpha_1^2+\beta_1^2-\alpha_2 \beta_2$ is equal to
The value of ${(\sqrt 2 + 1)^6} + {(\sqrt 2 - 1)^6}$ will be
A line with direction ratios $2,1,2$ meets the lines $x=y+2=z$ and $x+2=2 y=2 z$ respectively at the point $P$ and $Q$. if the length of the perpendicular from the point $(1,2,12)$ to the line $\mathrm{PQ}$ is $l$, then $l^2$ is
If $\overrightarrow{ a }$ and $\overrightarrow{ b }$ are unit vectors, then the greatest value of $\sqrt{3}|\overrightarrow{ a }+\overrightarrow{ b }|+|\overrightarrow{ a }-\overrightarrow{ b }|$ is