MCQ
If $\cos A = \frac{3}{4}$, then $32\sin \frac{A}{2}\cos \frac{5}{2}A = $
- A$\sqrt 7 $
- ✓$ - \sqrt 7 $
- C$7$
- D$-7$
$L.H.S.$ $ = 16(\sin 3A - \sin 2A)$
$ = 16\sin A(3 - 4{\sin ^2}A - 2\cos A)$
$ = 16.\frac{{\sqrt 7 }}{4}\left( {3 - 4.\frac{7}{{16}} - 2.\frac{3}{4}} \right) = - \sqrt 7 $.
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($A$) There is exactly one choice for such $\vec{v}$
($B$) There are infinitely many choices for such $\vec{v}$
($C$) If $\hat{u}$ lies in the $x y$-plane then $\left|u_1\right|=\left|u_2\right|$
($D$) If $\hat{u}$ lies in the $x z$-plane then $2\left|u_1\right|=\left|u_3\right|$