MCQ
If $\cos \theta=\frac{4}{5}$ then $\tan \theta=?$
- ✓$\frac{3}{4}$
- B$\frac{5}{3}$
- C$\frac{4}{3}$
- D$\frac{3}{5}$
✓
Answer
Correct option: A.
$\frac{3}{4}$
$\cos \theta=\frac{4}{5}=\frac{A B}{A C}$
$\therefore B C^2=A C^2-A B^2$
$=25-16$
$=9$
$\Rightarrow B C=3$
$\therefore \tan \theta=\frac{B C}{A B}=\frac{3}{4}$
$\therefore B C^2=A C^2-A B^2$
$=25-16$
$=9$
$\Rightarrow B C=3$
$\therefore \tan \theta=\frac{B C}{A B}=\frac{3}{4}$
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