Question
If $\cos(\theta+\phi)=\text{m}\cos(\theta-\phi),$ then prove that $\tan \theta=\frac{1-\text{m}}{1+\text{m}}\cot\phi.$
[Hint: Express $\frac{\cos(\theta+\phi)}{\cos(\theta-\phi)}=\frac{\text{m}}{1}$ and apply Componendo and Dividendo]
[Hint: Express $\frac{\cos(\theta+\phi)}{\cos(\theta-\phi)}=\frac{\text{m}}{1}$ and apply Componendo and Dividendo]