Question
If $\Delta\text{H}$ for a reaction has a negative value, how would you know the sign requirement of $\Delta\text{S}$ for it so that the reaction is spontaneous at low temperatures?

Answer

$\Delta\text{S}$ must be positive, then only $\Delta\text{G}$ will be negative and reaction will spontaneous.
$\because\Delta\text{G}^\circ=\Delta\text{H}^\circ-\text{T}\Delta\text{S}^\circ$

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