MCQ
If $\frac{3^{2\text{x}-8}}{225}=\frac{5^3}{5^{\text{x}}},$ then x =
  • A
    2
  • B
    3
  • C
    5
  • D
    4

Answer

  1. 5
    Solution:
    We have to find the value of x provided $\frac{3^{2\text{x}-8}}{225}-=\frac{5^3}{5^\text{x}}$
    So,
    $\frac{3^{2\text{x}-8}}{225}-=\frac{5^3}{5^\text{x}}$
    By cross multiplication we get
    $3^{2\text{x}-8}\times5^\text{x}=3^2\times5^2\times5^3$
    By equating exponents we get
    $3^{2\text{x}-8}=3^2$
    $2\text{x}-8=2$
    $2\text{x}=2+8$
    $2\text{x}=10$
    $\text{x}=\frac{10}{2}$
    $\text{x}=5$
    And
    $5^{\text{x}}=5^{3+2}$
    $\text{x}=3+2$
    $\text{x}=5$
    Hence the correct choice is c.

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