MCQ
If $\frac{{4 + 3\sqrt 3 }}{{\sqrt {(7 + 4\sqrt 3 )} }} = a + \sqrt b ,$ then $(a,b) = $
- A$(12,1)$
- B$(1, 12)$
- ✓$(-1, 12)$
- D$(-12, 1)$
==> $\frac{{4 + 3\sqrt 3 }}{{2 + \sqrt 3 }} = a + \sqrt b $
==> $\frac{{(4 + 3\sqrt 3 )\,(2 - \sqrt 3 )}}{{(2 + \sqrt 3 )\,(2 - \sqrt 3 )}} = a + \sqrt b $
==> $ - 1 + 2\sqrt 3 = a + \sqrt b $
==> $ - 1 + \sqrt {12} = a + \sqrt b $; $\therefore $ $(a,\,b) = ( - 1,\,12)$.
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| Class | $0-4$ | $4-8$ | $8-12$ | $12-16$ | $16-20$ |
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