Maharashtra BoardEnglish MediumSTD 11 ScienceMathsComplex Numbers2 Marks
MCQ
If $\frac{c+i}{c-i}=a+i b$, where $a, b, c$ are real, then $a^2+b^2=$
✓
1
B
-1
C
$c^2$
D
$-c^2$
✓
Answer
Correct option: A.
1
(A) $\frac{ c + i }{ c - i }= a + ib$ $\quad\ldots(i)$ $\therefore \frac{ c - i }{ c + i }= a - ib$$\quad\ldots(ii)$ Multiplying (i) and (ii), we get $\frac{c^2+1}{c^2+1}=a^2+b^2 \Rightarrow a^2+b^2-1$
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