Question
If $\frac{\text{dy}}{\text{dx}}=3$ then y is equal to:
- 3x
- 0
- 3x + c
- $\frac{\text{x}}{3}+\text{c}$
Solution:
$\frac{\text{dy}}{\text{dx}}=3$
$\text{dy}=3\text{dx}$
$\int\text{dy}=\int3\text{dx}=3\text{x}+\text{c}$
$\therefore\text{y}=3\text{x}+\text{c}$
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