MCQ
If $\frac{\text{dy}}{\text{dx}}=\text{x}^{-3}$ then $y:$
- ✓$\frac{-1}{2\text{x}^{2}}+\text{c}$
- B$\frac{-\text{x}^{-4}}{4}+\text{c}$
- C$\frac{2}{\text{x}^{2}}+\text{c}$
- D$\frac{\text{x}^{-2}}{2}+\text{c}$
we have $\frac{\text{dy}}{\text{dx}}=\text{x}^{-3}$
$\Rightarrow dy = x^{-3} dx$
Integrating both sides
$\therefore\text{y}=\int\text{x}^{-3}\text{dx}=\frac{\text{x}^{-3 + 1}}{-3+1}+\text{c}=-\frac{1}{2\text{x}^2}+\text{c}$
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