MCQ
If $A = \left[ {\begin{array}{*{20}{c}}
1&1\\
0&1
\end{array}} \right]$ and $B = \left[ {\begin{array}{*{20}{c}}
{\frac{{\sqrt 3 }}{2}}&{\frac{1}{2}}\\
{\frac{{ - 1}}{2}}&{\frac{{\sqrt 3 }}{2}}
\end{array}} \right]$ , then $(BB^TA)^5$ is equal to
1&1\\
0&1
\end{array}} \right]$ and $B = \left[ {\begin{array}{*{20}{c}}
{\frac{{\sqrt 3 }}{2}}&{\frac{1}{2}}\\
{\frac{{ - 1}}{2}}&{\frac{{\sqrt 3 }}{2}}
\end{array}} \right]$ , then $(BB^TA)^5$ is equal to
- A$\left[ {\begin{array}{*{20}{c}}
{2 + \sqrt 3 }&1\\
{ - 1}&{2 - \sqrt 3 }
\end{array}} \right]$ - B$\frac{1}{2}\left[ {\begin{array}{*{20}{c}}
1&5\\
0&1
\end{array}} \right]$ - ✓$\left[ {\begin{array}{*{20}{c}}
1&5\\
0&1
\end{array}} \right]$ - D$\left[ {\begin{array}{*{20}{c}}
5&1\\
0&1
\end{array}} \right]$