If e^ y (x + 1) = 1, then show that d^ 2 y dx^ 2 = ( dy dx )^ 2 . - Vidyadip

Question

If $e^{y }(x + 1) = 1,$ then show that $\frac{\text{d}^{2}\text{y}}{\text{dx}^{2}} = \bigg(\frac{\text{dy}}{\text{dx}}\bigg)^{2}.$

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Answer

$\text{e}^{\text{y}.} \text{(x + 1)} = 1 $
$\Rightarrow \text{e}^{\text{y}}. \text{1 + (x + 1)}.\text{e}^{\text{y}}.\frac{\text{dy}}{\text{d}} = 0$
$\Rightarrow \frac{\text{dy}}{\text{dx}} = -\frac{1}{\text{(x + 1)}}$
$\frac{\text{d}^{2}\text{y}}{\text{dx}^{2}} = + \frac{1}{\text{(x + 1)}^{2}} = \big(\frac{\text{dy}}{\text{dx}}\big)^{2}$

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