MCQ
If $f (x)=\sqrt{x-2}, 2< x< 4$, then
  • f(x) is continuous in (2, 4)
  • B
    f(x) is discontinuous in (2, 4)
  • C
    f(x) is continuous in (2, 4) except at x = 3
  • D
    f(x) is discontinuous in (2, 4) except at x = 3

Answer

Correct option: A.
f(x) is continuous in (2, 4)
(A)
$\lim _{x \rightarrow 3} f (x)=\lim _{x \rightarrow 3} \sqrt{x-2}=1$
$f(3)=\sqrt{3-2}=1$
$\therefore \quad \lim _{x \rightarrow 3} f (x)= f (3)$
$\therefore f (x)$ is continuous at $x=3$.
Since $3 \in(2,4)$
$\therefore f (x)$ is continuous in $(2,4)$.

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