MCQ
If $F(\alpha ) = \left[ {\begin{array}{*{20}{c}}{\cos \alpha }&{ - \sin \alpha }&0\\{\sin \alpha }&{\cos \alpha }&0\\0&0&1\end{array}} \right]$ and $G\,(\beta ) = \left[ {\begin{array}{*{20}{c}}{\cos \beta }&0&{\sin \beta }\\0&1&0\\{ - \sin \beta }&0&{\cos \beta }\end{array}} \right]$, then ${[F(\alpha )\,G(\beta )]^{ - 1}} = $
  • A
    $F(\alpha )\, - G(\beta )$
  • B
    $ - F(\alpha )\, - G(\beta )$
  • C
    ${[F(\alpha )]^{ - 1}}\,{[G(\beta )]^{ - 1}}$
  • ${[G(\beta )]^{ - 1}}{[F(\alpha )]^{ - 1}}$

Answer

Correct option: D.
${[G(\beta )]^{ - 1}}{[F(\alpha )]^{ - 1}}$
d
(d) Since ${(AB)^{ - 1}} = {B^{ - 1}}{A^{ - 1}}$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free