Question
If $f(m)=m^2-3 m+1$, find : $f\left(\frac{1}{2}\right)$

Answer

$
\begin{aligned}
& f\left(\frac{1}{2}\right)=\left(\frac{1}{2}\right)^2-3\left(\frac{1}{2}\right)+1 \\
& =\frac{1}{4}-\frac{3}{2}+1 \\
& =\frac{1-6+4}{4} \\
& =-\frac{1}{4} \\
&
\end{aligned}
$

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