MCQ
If for any A.P. d = 5 then t18 – t13 = ...
- A5
- B
- ✓25
- D
✓
Answer
Correct option: C.
25
(C) 25
Given d = 5
Now, By using nth term of an A.P. formula
tn = a + (n – 1)d
where n = no. of terms
a = first term
d = common difference
tn = nth terms
Thus, t18 – t13 = [a + (18 – 1) × 5] – [ a + (13 – 1) × 5]
⇒ t18 – t13 = [ 17 × 5] – [ 12 × 5]
⇒ t18 – t13 = 85 – 60 = 25
Thus, correct answer is (C)
Given d = 5
Now, By using nth term of an A.P. formula
tn = a + (n – 1)d
where n = no. of terms
a = first term
d = common difference
tn = nth terms
Thus, t18 – t13 = [a + (18 – 1) × 5] – [ a + (13 – 1) × 5]
⇒ t18 – t13 = [ 17 × 5] – [ 12 × 5]
⇒ t18 – t13 = 85 – 60 = 25
Thus, correct answer is (C)
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