MCQ
If $\forall\text{m}\in\text{N},$ then $11^{m+2}+ 12^{2m-1}$ is divisible by:
  • A
    $121$
  • B
    $132$
  • $133$
  • D
    None of these

Answer

Correct option: C.
$133$
To find the divisor of $11^{m+2}+ 12^{2m-1}$ by mathematic induction, the first step is to check for the smallest natural number,
i.e; for $m = 1.$
So, this reduces to $11^3+ 12^1$ or $11^4+ 1$.
So, the number when divided by $11$ leaves remainder $1.$
So, we can knock out options $A$ and $B$ as $121$ as well as $132$ are both divisible by $11$ and
hence their multiples will always be divisible by $11.$
Now, we have to check the divisibility of $11^{m+2}+ 12^{2m-1}$ by $133.$
For $m = 1, 11^4+ 1$ is not divisible by $133.$
So, we can knock out option $C.$

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