If force $F$ , velocity $V$ and time $T$ are taken as fundamental units then dimension of force in the pressure is
A$3$
B$5$
C$6$
D$1$
Medium
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D$1$
d $[\text { Pressure }]$
$=\left[\frac{\text { Force }}{\text { Area }}\right]=\left[\frac{\mathrm{F}}{(\mathrm{VT})^{2}}\right]=\left[\mathrm{F}^{1} \mathrm{V}^{-2} \mathrm{T}^{-2}\right]$
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