MCQ
If $\frac{\text{a}}{\text{b}}+\frac{\text{b}}{\text{a}}=1,$ then $a^3 + b^3 =$
  • A
    $1$
  • B
    $-1$
  • C
    $\frac{1}{2}$
  • $0$

Answer

Correct option: D.
$0$
$\frac{\text{a}}{\text{b}}+\frac{\text{b}}{\text{a}}=1\Rightarrow\text{a}^2+\text{b}^2-\text{ab}=0$
Now by identity $a^3 + b^3 = (a + b)(a^2 + b^2 - ab).$
if $a^2 + b^2 - ab = 0.$
then $a^3 + b^3 = 0$
Hence, correct option is $(d).$

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