Question
If function $f(x)=\frac{\sqrt{x}-\sqrt{a}}{x-a}$, is continuous at $x=a$, then find value of $f(a)$.

Answer

value of $\text{R.H.L.}$
$\lim _{h \rightarrow 0} f(a+0)=\lim _{h \rightarrow 0} \frac{a+h-a}{\sqrt{a+h}-\sqrt{a}}$
$=\lim _{h \rightarrow 0}\left[\frac{h}{\sqrt{a+h}-\sqrt{a}} \times \frac{\sqrt{a+h}+\sqrt{a}}{\sqrt{a+h}+\sqrt{a}}\right] $
$=\lim _{h \rightarrow 0} h \frac{(\sqrt{a+h}+\sqrt{a})}{a+h-a} $
$=\lim _{h \rightarrow 0} \frac{h(\sqrt{a+h}+\sqrt{a})}{h}=\sqrt{a}+\sqrt{a} $
$=2 \sqrt{a}$
$\because$function is continuous at $x=a$.
$ \begin{array}{rlrl} \therefore & f(a)  =\lim _{h \rightarrow 0} f(a+h) \\ & \therefore f(a) =2 \sqrt{a} \end{array} $

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