Question
If $f(x)=2 x^3-13 x^2+17 x+12$,
Find: $f (0)$
Find: $f (0)$
✓
Answer
The given polynomial is $f(x)=2 x^3-13 x^2+17 x+12$
$f(0)$
we need to substitute the ' $(0)^{\prime}$ in $f(x)$
$f(0)=2(0)^3-13(0)^2+17(0)+12$
$=(2 \times 0)-(13 \times 0)+(17 \times 0)+12$
$=0-0+0+12$
$=12$
therefore $f(0)=12$
$f(0)$
we need to substitute the ' $(0)^{\prime}$ in $f(x)$
$f(0)=2(0)^3-13(0)^2+17(0)+12$
$=(2 \times 0)-(13 \times 0)+(17 \times 0)+12$
$=0-0+0+12$
$=12$
therefore $f(0)=12$
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