MCQ
If $f(x) = 4{x^3} + 3{x^2} + 3x + 4$, then ${x^3}f\left( {\frac{1}{x}} \right)$ is
- A$f( - x)$
- B$\frac{1}{{f(x)}}$
- C${\left( {f\left( {\frac{1}{x}} \right)} \right)^2}$
- ✓$f(x)$
$ = 4 + 3x + 3{x^2} + 4{x^3} = f(x)$.
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