MCQ
If $f(x) = ax + b$ and $g(x) = cx + d$, then $f(g(x)) = g(f(x))$ is equivalent to
- A$f(a) = g(c)$
- B$f(b) = g(b)$
- ✓$f(d) = g(b)$
- D$f(c) = g(a)$
==> $f(cx + d) = g(ax + b)$
==> $a[cx + d] + b = c[ax + b] + d$
==> $ad + b = cb + d$==> $f(d) = g(b)$.
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