MCQ
If $f(x) = (ax^2 + b)^3,$ then the function $g$ such that $f(g(x)) = g(f(x))$ is given by:
- A$\text{g}(\text{x})=\Big(\frac{\text{b}-\text{x}^\frac{1}{3}}{\text{a}}\Big)$
- B$\text{g}(\text{x})=\frac{1}{(\text{ax}^2+\text{b})^3}$
- C$\text{g}(\text{x})=(\text{ax}^2+\text{b})^\frac{1}{3}$
- ✓$\text{g}(\text{x})=\Big(\frac{\text{x}^\frac{1}{3}-\text{b}}{\text{a}}\Big)^\frac{1}{2}$