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If $f(x) = (ax^2 – b)^3$, then the function $g$ such that $f{g(x)} = g{f(x)}$ is given by:

• A
  $\text{g(x)}=\Big(\frac{\text{b}-\text{x}^\frac{1}{3}}{\text{a}}\Big)^\frac{1}{2}$
• B
  $\text{g(x)}=\frac{1}{(\text{ax}^2+\text{b})^3}$
• C
  $\text{g(x)}=(\text{ax}^2+\text{b})^\frac{1}{3}$
• ✓
  $\text{g(x)}=\Big(\frac{\text{x}^\frac{1}{3}+\text{b}}{\text{a}}\Big)^\frac{1}{2}$