MCQ
If $f(x)=\left(a x^2-b\right)^3$, then the function $g$ such that $f\{g(x)\}=g\{f(x)\}$ is given by:
- A$\text{g(x)}=\Big(\frac{\text{b}-\text{x}^\frac{1}{3}}{\text{a}}\Big)^\frac{1}{2}$
- B$\text{g(x)}=\frac{1}{(\text{ax}^2+\text{b})^3}$
- C$\text{g(x)}=(\text{ax}^2+\text{b})^\frac{1}{3}$
- ✓$\text{g(x)}=\Big(\frac{\text{x}^\frac{1}{3}+\text{b}}{\text{a}}\Big)^\frac{1}{2}$