- A$m^2+1$
- B$m^2-M$
- C$M^2+1$
- ✓$m^2+M$
$+\sin \left(\cot ^{-1}\left(\cos \left(\frac{\pi}{2}-\cos ^{-1} x\right)\right)\right)$
$=\cos \left(\tan ^{-1}\left(\sin \left(\cos ^{-1} x\right)\right)\right)+\sin \left(\cot ^{-1}\left(\sin \left(\cos ^{-1} x\right)\right)\right)$
$=\cos \left(\tan ^{-1}\left(\sin \left(\cos ^{-1} x\right)\right)\right)+\sin \left(\frac{\pi}{2}-\tan ^{-1}\left(\sin \left(\cos ^{-1} x\right)\right)\right)$
$=\cos \left(\tan ^{-1}\left(\sin \left(\cos ^{-1} x\right)\right)\right)+\cos \left(\tan ^{-1}\left(\sin \left(\cos ^{-1} x\right)\right)\right)$
$=2 \cos \left(\tan ^{-1}\left(\sin \left(\cos ^{-1} x\right)\right)\right)=\frac{2}{\sqrt{2-x^{2}}} \in[\sqrt{2}, 2]$
From graph, Number of solutions of
Sgn $\left( {\left| {x - 1} \right| - 2} \right) = \ln \left| {x - 2} \right|$ is $4$
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$I$. $A(t) < 0$ for all $t$.
$II$. $A(t)$ has infinitely many critical points.
$III.$ $A(t)=0$ for infinitely many $t$.
$IV$. $A^{\prime}(t) < 0$ for all $t$.