MCQ
If $f(x) = \frac{{1 - x}}{{1 + x}},$ then $f[f(\cos \;2\theta )] = $
- A$\tan 2\theta $
- B$\sec 2\theta $
- ✓$\cos 2\theta $
- D$\cot 2\theta $
$ = f({\tan ^2}\theta ) = \frac{{1 - {{\tan }^2}\theta }}{{1 + {{\tan }^2}\theta }} = \cos \,\,2\theta .$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.