MCQ
If $f(x) = \frac{{1 - x}}{{1 + x}},$ then $f[f(\cos \;2\theta )] = $
  • A
    $\tan 2\theta $
  • B
    $\sec 2\theta $
  • $\cos 2\theta $
  • D
    $\cot 2\theta $

Answer

Correct option: C.
$\cos 2\theta $
c
(c) $f[f(\cos \,\,2\theta )] = f\,\left[ {\frac{{1 - \cos \,\,2\theta }}{{1 + \cos \,\,2\theta }}} \right]$

$ = f({\tan ^2}\theta ) = \frac{{1 - {{\tan }^2}\theta }}{{1 + {{\tan }^2}\theta }} = \cos \,\,2\theta .$

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