MCQ
If $f(x) = \frac{{2x + 1}}{{3x - 2}}$, then $(fof)(2)$ is equal to
- A$1$
- B$3$
- C$4$
- ✓$2$
Hence $(fof)(2) = f(f(2)) = f\left( {\frac{5}{4}} \right) $
$= \frac{{2 \times \frac{5}{4} + 1}}{{3 \times \frac{5}{4} - 2}} = 2$.
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