MCQ
If $\text{f}(\text{x})=\frac{\text{x}-4}{2\sqrt{\text{x}}}$ then $f'(1)$ is equal to:
  • $\frac{5}{4}$ 
  • B
    $\frac{4}{5}$ 
  • C
    $1$ 
  • D
    $0$

Answer

Correct option: A.
$\frac{5}{4}$ 
Given that $\text{f}(\text{x})=\frac{\text{x}-4}{2\sqrt{\text{x}}}$ 
$\therefore\text{f}(\text{x})=\frac{1}{2}\bigg[\frac{\sqrt{\text{x}.}1-(\text{x}-4).\frac{1}{2\sqrt{\text{x}}}}{\text{x}}\bigg]$
$=\frac{1}{2}\Big[\frac{2\text{x}-\text{x}+4}{2\sqrt{\text{x}.\text{x}}}\Big]$
$=\frac{1}{2}\Bigg[\frac{\text{x}+4}{2(\text{x})^{\frac{3}{2}}}\Bigg]$
$\therefore\text{f}(\text{x})\ \text{x}=1=\frac{1}{2}\Big[\frac{1+4}{2\times1}\Big]$
$=\frac{5}{4}$

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