MCQ
If $f(x) = \frac{x}{{1 + x}}$, then ${f^{ - 1}}(x)$ is equal to
- A$\frac{{(1 + x)}}{x}$
- B$\frac{1}{{(1 + x)}}$
- C$\frac{{(1 + x)}}{{(1 - x)}}$
- ✓$\frac{x}{{(1 - x)}}$
$\therefore$ $y = \frac{x}{{1 + x}} \Rightarrow y + yx = x$
==> $x = \frac{y}{{1 - y}}$
==> ${f^{ - 1}}(y) = \frac{y}{{1 - y}}$
==> ${f^{ - 1}}(x) = \frac{x}{{1 - x}}$.
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